Polynomials Concepts and Practice Questions

Polynomials Concepts and Practice Questions Guide: Master Basics & Score High Easily!

Polynomials Concepts and Practice Questions Guide

Have you ever looked at an algebraic expression and felt confused about what it really means? You’re not alone.
Imagine this: A student preparing for an exam keeps skipping polynomial questions because they “look complicated.” But once they understand just a few simple concepts, those same questions become the easiest marks on the paper.

That’s the power of Polynomials.
In this guide, I’ll break down polynomials in a super simple, friendly way—just like a teacher sitting next to you. By the end, you won’t just understand polynomials… you’ll actually enjoy solving them!

Sets Explained for POLYCET 2026 Master Concepts Fast & Score High

What Are Polynomials?

An algebraic expression becomes a polynomial if the powers of the variable(s) are whole numbers

Example: 2x – 5, 3x2 + 5x – 3 , x3 + 3x2 – 6x + 3

Value of a polynomial

p(a) is the value of a polynomial p(x) at x = a, whre a is any real number

Ex:  let p (x) = 2x + 5

                 Put x = 1 ⟹ p (1) =  2 (1) + 5 = 2 + 5 = 7

∴ 7 is the value of the polynomial p(x) at x = 1

Zero of a polynomial

Zero of a polynomial p(x) is any real number ‘k’ such that p(k) = 0.

Ex:  let p (x) = x  + 5

           Put x = 5 ⟹ p (– 5) =  – 5 + 5 = 0

∴ – 5 is the zero of the polynomial p(x)

Note:  For finding the zeroes of the polynomial p(x), let p(x) = 0

Degree of a polynomial

The highest power of x in a polynomial p(x) is called the degree of the polynomial p(x)

Example: Degree of the polynomial 3x2 – 4x is 2

Degree of the polynomial x3 – 4x4 – 5x + 6  is 4

Types of Polynomials

According to Terms

1. Monomial:  If a polynomial has only one term, then it is called a monomial.

Example: 2x, 3y, -5x, 9x3

2.  Binomial: If a polynomial has two terms, then it is called a Binomial.

Example: 2x + 1, 3y – 7, -5x + 6, x5 + 5x3

3. Trinomial:  If a polynomial has three terms, then it is called a Trinomial.

Example: x5 + 5x3+ 2x, 3y2 – 8y2 + 3

According to the degree

1. Linear Polynomial:  If a polynomial has a degree of one, then it is called a Linear Polynomial.

Example: 2x + 1, 3y – 1,

2.  Quadratic Polynomial: If a polynomial has a degree of two, then it is called a Quadratic Polynomial.

Example: 2x2  +  x + 1, y2  – 7, -x2  + 6,

3. Cubic Polynomial: If a polynomial has a degree of three, then it is called a Cubic Polynomial.

Example: 5x3+ 2x, 9y3 – 8y2 + 3

Note:

For any quadratic polynomial ax2 + bx + c, a ≠ 0, the graph of the corresponding equation y = ax2 + bx + c (a ≠ 0,) either opens upwards like ∪ or opens downwards ∩ as This depends on whether a > 0 or a< 0.

The shape of these curves is called a parabola

Graphical Representation of a Quadratic Polynomial

The shape of the graph of y = ax2 + bx + c, (a ≠ 0), the following three cases arise.

Case (i) :

Here, the graph cuts X – axis at two distinct points. In this case, the x-coordinates of those two points are the two zeroes of the quadratic polynomial ax2 + bx + c. The parabola opens either upward or downward.

Polynomials Concepts and Practice Questions 2

Case (ii) :

Here, the graph touches X – axis at exactly one point. In this case, the x-coordinate of that point is the only zero for the quadratic polynomial ax2 + bx + c.

Polynomials Concepts and Practice Questions 3

Case (iii) :

Here, the graph is either completely above the X-axis or completely below the X – axis.

So, it does not cut the X-axis at any point.

The quadratic polynomial ax2 + bx + c has no zero in this case.

Polynomials Concepts and Practice Questions 4

 

Relationship Between Zeros and Coefficients of the polynomial:

 1. P(x) = ax + b is linear polynomial

zero of the polynomial is x = −b/a = -(constant)/ x coefficient

2. P(x) = ax2 + bx + c (a ≠ 0) is the general form of a quadratic polynomial.

Sum of the zeroes = α + β =  −b/a = -(x coefficient)/ x2 coefficient

Product of the zeroes =−b/a = (constant)/ x2 coefficient

 3. p(x) = ax3 + bx2 + cx + d ( a ≠ 0)is the general form of a cubic polynomial.

α + β + γ = −b/a = -(x2 constant)/ x3 coefficient

αβ + βγ + γα  = −b/a = (x constant)/ x3 coefficient

α β γ = −−b/a = -(constant)/ x3 coefficient

  •       If α and β are the zeroes of a quadratic polynomial, then its form is k [x2 – (α + β ) x + α β]
  •      If α, β and γ are the zeroes of the cubic polynomial, then its form is

k [x3 – (α + β + γ) x2 +( αβ + βγ +γα  )x – αβγ]

Polynomials Concepts and Practice Questions

Division Algorithm for the polynomials:

If p(x) and g(x) are any two polynomials with g(x) ¹ 0, then we can find polynomials

q(x) and r(x) such that p(x) = g(x) × q(x) + r(x),

Where either r(x) = 0 or degree of r(x) < degree of g(x) if r(x) ≠ 0

We have the following results from the above discussions

(i)  If g(x) is a linear polynomial then r(x) = r is a constant.

(ii)  If degree of g(x) = 1, then degree of p(x) = 1 + degree of q(x).

(iii)  If p(x) is divided by (x – a), then the remainder is p(a).

(iv)  If r = 0, we say q(x) divides p(x) exactly or q(x) is a factor of p(x)

Polynomials Concepts and Practice Questions 5

Polynomials Concepts and Practice Questions

Solved Questions With Answers

1. The zeroes of the quadratic polynomial x2  + 24x + 119 are.

(1) one positive and one negative        (2) both positive

(3) both negative      (4) none of the above

Answer: ( 3 )

Solution:

x2  + 24x + 119 = x2  + 17x + 7x + 119

= x(x + 17) + 7(x + 17)

= (x + 7) (x + 17)

Zeros are  – 7, –17

2. What is the degree of the polynomial 7u6 – 3/2u4 + 6u2 – 8

(1)  7 (2) –3/2    (3)  6      (4) – 8

Answer: ( 3 )

Solution:

The highest power of x in a polynomial p(x) is called the degree of the polynomial p(x)

Degree of the polynomial 7u6 – 3/2u4 + 6u2 – 8   is 6

3.  If x3 – 3x2 + 4x + k is exactly divisible by x – 2, then k =

(1) 4  (2) – 4    (3)  0      (4)  1

Answer: ( 2 )

Solution:

P(x) = x3 – 3x2 + 4x + k is exactly divisible by x – 2

⇒ P(2) = 0

    (2)3 – 3(2)2 + 4(2) + k = 0

    8 – 12 + 8 + k = 0

k = – 4

Polynomials Concepts and Practice Questions

 

4.  The remainder of  3x3 – 2x2 + x +  2 when divided by 3x + 1 is

(1) 4/3  (2) 3/4    (3) – 4/3   (4)  None

Answer: ( 4 )

Solution:

P(x) =  3x3 – 2x2 + x +  2

⇒ Remainder = P(1/3) =  3(–1/3)3 – 2(–1/3)2 + (–1/3) + 2 

= – 3/27 – 2/9 – 1/3 + 2

= – 1/9 – 2/9 – 1/3 + 2

                                          = (1– 2 – 3 + 18)/9 

                                          = (19 – 5)/9 

                                          = 14/9 

5.  If  two zeroes of the polynomial x3 + 3x2 – 5x – 15 are √5 and – √5, then the third zero is

(1) 3  (2) 5    (3) – 3   (4) – 5

Answer: ( 3 )

Solution:

P(x) = x3 + 3x2 – 5x – 15

α + β + γ = -b/a = – 3

√5 – √5 + γ = – 3

γ = – 3

 

 


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