polycet solved previous qp 2020

Ts polycet | Maths solved previous qp 2020 || Solved Papers

Chapter 4: Linear equations in Two Variables

1.For the equation 2019x + 2020y = 4040, when x= 0 the value of y =
    2019x + 2020y = 4040 అను సమీకరణమునకు x= 0 అయిన, y విలువ
  (1) 2020           (2) 2019                     
   (3) 4                (4) 2           

Answer: (4)

   

2. Solution of the equations 7x + 5y = 12 and 5x – 7y = – 2, not equal to
     7x + 5y = 12 మరియు 5x – 7y = – 2 సమీకరణాల సాధన ఈ క్రిది వానీలో దేనికి సమాన కాదు
TS POLYCET 2020 - Linear equations in 2 variables 1

Answer:   (1)

                                      

3. If TS POLYCET 2020 - Linear equations in 2 variables 2 then (x, y) =

  TS POLYCET 2020 - Linear equations in 2 variables 3 అయిన,(x, y) =

(1) (2019, 2020)         (2) (2020, 2019)

(3)  (2019, 2019)       (4) (2020, 2020)

Answer:   (1)

   

4. If (5, 2) is the solution 2x + 3y = 20, ax – by = 0, the (a, b) =
    2x + 3y = 20, ax – by = 0 ల సాధన (5, 2) అయిన (a, b) =  
     (1) (2, 5)                         (2) (5, 2)                            
     (3) (– 2, 5)                   (4) (– 5, 2)   

Answer: (1)                          

   

5. If the system of equations x – y = 1 and ax + y = 2 has unique solution then
      జత సమీకరణాలకు x – y = 1, ax + y = 2 లకు ఏకైక సాధన ఉంటే
     (1) a = 1                        (2) a = – 1                           
     (3) a ≠ 1                        (4)  a ≠– 1

Answer:   (4)                        

   

6. x + y = TS POLYCET 2020 - Linear equations in 2 variables 6 , x – y = 0, then x =
    x + y =TS POLYCET 2020 - Linear equations in 2 variables 6 , x – y = 0, అయిన x =
TS POLYCET 2020 - Linear equations in 2 variables 8

Answer:   (3)                        

   

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